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x^2=3^10
We move all terms to the left:
x^2-(3^10)=0
We add all the numbers together, and all the variables
x^2-59049=0
a = 1; b = 0; c = -59049;
Δ = b2-4ac
Δ = 02-4·1·(-59049)
Δ = 236196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{236196}=486$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-486}{2*1}=\frac{-486}{2} =-243 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+486}{2*1}=\frac{486}{2} =243 $
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